Statement: Add the contents of memory locations 40001H and 4001H and place the result in the memory locations 4002Hand 4003H.

Sample problem: (4000H) = 7FH (400lH)  = 89H          Result    = 7FH + 89H = lO8H (4002H) = 08H (4003H) = 0lH Source program: LXI H, 4000H :HL Points 4000H MOV A, M :Get first operand INX H :HL Points 4001H ADD M :Add second operand INX H :HL Points 4002H MOV M, A :Store the lower byte of result at 4002H MVIA, 00 :Initialize higher byte result with 00H ADC A :Add carry in the high byte result INX H :HL Points 4003H MOV M, A :Store the higher byte of result at 4003H HLT :Terminate program execution